In npn transistor circuit the collector current is 10 mA. If 90% of the electrons reach the collector, then emitter current will be:

Question

In npn transistor circuit the collector current is 10 mA. If 90% of the electrons reach the collector, then emitter current will be: (A) 0.1 mA (B) 1 mA (C) 9 mA (D) near by 11 mA

Tardigrade Admin · Accepted Answer

Given, ic=10mA,ic=(9/10)× ie So, 10=(9/10)× ie or ie=(100/9)≈ 11mA

Q. In npn transistor circuit the collector current is 10 mA. If 90% of the electrons reach the collector, then emitter current will be:

0.1 mA

1 mA

9 mA

near by 11 mA

Given, $i_{c} = 10 m A, i_{c} = \frac{9}{10} \times i_{e}$ So, $10 = \frac{9}{10} \times i_{e}$ or $i_{e} = \frac{100}{9} \approx 11 m A$

Q. In npn transistor circuit the collector current is 10 mA. If 90% of the electrons reach the collector, then emitter current will be:

0.1 mA

1 mA

9 mA

near by 11 mA

Given, ic​=10mA,ic​=109​×ie​ So, 10=109​×ie​ or ie​=9100​≈11mA

Given, $i_{c} = 10 m A, i_{c} = \frac{9}{10} \times i_{e}$ So, $10 = \frac{9}{10} \times i_{e}$ or $i_{e} = \frac{100}{9} \approx 11 m A$