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Q. In npn transistor circuit the collector current is 10 mA. If 90% of the electrons reach the collector, then emitter current will be:

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Solution:

Given, $ {{i}_{c}}=10mA,{{i}_{c}}=\frac{9}{10}\times {{i}_{e}} $ So, $ 10=\frac{9}{10}\times {{i}_{e}} $ or $ {{i}_{e}}=\frac{100}{9}\approx 11mA $