In nitrogen family, the H -M- H bond angle in the hydrides gradually becomes closer to 90° on going form N to Sb. This shows that gradually

Question

In nitrogen family, the H -M- H bond angle in the hydrides gradually becomes closer to 90° on going form N to Sb. This shows that gradually (A) the basic strength of the hydrides increases (B) almost pure p -orbitals are used for M- H bonds (C) the bond energies of M- H bonds increase (D) the bond pairs of electrons become nearer to the central atom.

Tardigrade Admin · Accepted Answer

On moving down the group, electronegativity decreases, consequently bond pair shifts more and more away from the central atom. Hence, H -M- H bond angle decreases and becomes closer to 90° in SbH 3 which reveals that almost pure p -orbitals are used for M- H bonding.

Q. In nitrogen family, the $H - M - H$ bond angle in the hydrides gradually becomes closer to $9 0^{\circ}$ on going form $N$ to $S b$ . This shows that gradually

the basic strength of the hydrides increases

almost pure $p$ -orbitals are used for $M - H$ bonds

the bond energies of $M - H$ bonds increase

the bond pairs of electrons become nearer to the central atom.

On moving down the group, electronegativity decreases, consequently bond pair shifts more and more away from the central atom. Hence, $H - M - H$ bond angle decreases and becomes closer to $9 0^{\circ}$ in $S b H_{3}$ which reveals that almost pure $p$ -orbitals are used for $M - H$ bonding.

Q. In nitrogen family, the H−M−H bond angle in the hydrides gradually becomes closer to 90∘ on going form N to Sb. This shows that gradually

the basic strength of the hydrides increases

almost pure p -orbitals are used for M−H bonds

the bond energies of M−H bonds increase

the bond pairs of electrons become nearer to the central atom.

On moving down the group, electronegativity decreases, consequently bond pair shifts more and more away from the central atom. Hence, H−M−H bond angle decreases and becomes closer to 90∘ in SbH3​ which reveals that almost pure p -orbitals are used for M−H bonding.

Q. In nitrogen family, the $H - M - H$ bond angle in the hydrides gradually becomes closer to $9 0^{\circ}$ on going form $N$ to $S b$ . This shows that gradually

almost pure $p$ -orbitals are used for $M - H$ bonds

the bond energies of $M - H$ bonds increase

On moving down the group, electronegativity decreases, consequently bond pair shifts more and more away from the central atom. Hence, $H - M - H$ bond angle decreases and becomes closer to $9 0^{\circ}$ in $S b H_{3}$ which reveals that almost pure $p$ -orbitals are used for $M - H$ bonding.