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Tardigrade
Question
Mathematics
In n is odd and Cr = nCr then the value of C20-C21+C22-C23+.....+(-1)nC2n is
Q. In n is odd and
C
r
=
n
C
r
then the value of
C
0
2
−
C
1
2
+
C
2
2
−
C
3
2
+
.....
+
(
−
1
)
n
C
n
2
is
1357
173
Binomial Theorem
Report Error
A
0
20%
B
2
2
n
−
2
60%
C
2
n
C
n
20%
D
2
2
n
0%
Solution:
Correct answer is (a) 0