In metal oxide, O2 - ions are arranged in hcp lattice while metal ions occupy (2/3)rd of octahedral voids. The simplest formula of oxide is

Question

In metal oxide, O2 - ions are arranged in hcp lattice while metal ions occupy (2/3)rd of octahedral voids. The simplest formula of oxide is (A) MO (B) M2O3 (C) MO2 (D) M2O

Tardigrade Admin · Accepted Answer

Number of O2 - ions = n Number of octahedral voids = n Number of Mn + ions =(2/3)n Ratio of M and O=(2/3)n:n = 2: 3 So simplest formula of solid =M2O3 .

Q. In metal oxide, $O^{2 -}$ ions are arranged in hcp lattice while metal ions occupy $\frac{2}{3} r d$ of octahedral voids. The simplest formula of oxide is

MO

$M_{2} O_{3}$

$M O_{2}$

$M_{2} O$

Number of $O^{2 -}$ ions = n

Number of octahedral voids = n

Number of $M^{n +}$ ions $= \frac{2}{3} n$

Ratio of M and $O = \frac{2}{3} n : n$

= 2 : 3

So simplest formula of solid $= M_{2} O_{3}$ .

Q. In metal oxide, O2− ions are arranged in hcp lattice while metal ions occupy 32​rd of octahedral voids. The simplest formula of oxide is

MO

M2​O3​

MO2​

M2​O

Number of O2− ions = n Number of octahedral voids = n Number of Mn+ ions =32​n Ratio of M and O=32​n:n = 2 : 3 So simplest formula of solid =M2​O3​ .

Q. In metal oxide, $O^{2 -}$ ions are arranged in hcp lattice while metal ions occupy $\frac{2}{3} r d$ of octahedral voids. The simplest formula of oxide is

$M_{2} O_{3}$

$M O_{2}$

$M_{2} O$

Number of $O^{2 -}$ ions = n

Number of octahedral voids = n

Number of $M^{n +}$ ions $= \frac{2}{3} n$

Ratio of M and $O = \frac{2}{3} n : n$

= 2 : 3

So simplest formula of solid $= M_{2} O_{3}$ .