Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
In Mayer's relation, CP-CV=R 'R' stands for
Q. In Mayer's relation,
C
P
−
C
V
=
R
'R' stands for
1361
220
NTA Abhyas
NTA Abhyas 2020
Thermodynamics
Report Error
A
translational kinetic energy of 1 mol gas
0%
B
rotational kinetic energy of 1 mol gas
0%
C
vibrational kinetic energy of 1 mol gas
33%
D
work done to increase the temperature of 1 mol gas by one degree
67%
Solution:
PV = RT (For 1 mol) …(i)
P
(
V
+
Δ
V
)
=
R
(
T
+
1
)
…(ii)
From equation (i) and (ii),
P
Δ
V
=
R
i.e., W = R (work done).