In Mayer's relation, CP-CV=R 'R' stands for

Question

In Mayer's relation, CP-CV=R 'R' stands for (A) translational kinetic energy of 1 mol gas (B) rotational kinetic energy of 1 mol gas (C) vibrational kinetic energy of 1 mol gas (D) work done to increase the temperature of 1 mol gas by one degree

Tardigrade Admin · Accepted Answer

PV = RT (For 1 mol) ....(i) P(V + Δ V)=R(T + 1) .... (ii) From equation (i) and (ii), PΔ V=RΔ T Δ H=Δ U+Δ (PV)(nC)pΔ T=(nC)vΔ T+nRΔ TCp-Cv=R

Q. In Mayer's relation, $C_{P} - C_{V} = R$
' $R$ ' stands for

translational kinetic energy of 1 mol gas

rotational kinetic energy of 1 mol gas

vibrational kinetic energy of 1 mol gas

work done to increase the temperature of 1 mol gas by one degree

$P V = RT$ (For $1$ mol) ....(i)
$P (V + Δ V) = R (T + 1)$ .... (ii)
From equation (i) and (ii),
$P Δ V = R Δ T$
$Δ H = Δ U + Δ (P V) (n C)_{p} Δ T = (n C)_{v} Δ T + n R Δ T C_{p} - C_{v} = R$

Q. In Mayer's relation, CP​−CV​=R 'R' stands for