Tardigrade
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Tardigrade
Question
Chemistry
In K4[Fe(CN)6], Fe is in the form of
Q. In
K
4
[
F
e
(
CN
)
6
]
,
F
e
is in the form of
1892
192
Coordination Compounds
Report Error
A
An atom
14%
B
An ion
22%
C
Cationic complex
23%
D
Anionic complex
41%
Solution:
K
4
[
F
e
(
CN
)
6
]
→
4
K
+
+
[
F
e
(
CN
)
6
]
4
−
Complex has negative charge so it is anionic complex.