Question

In $K_{3}Cr{(C_2{O}_4)}_3$ the coordination number and oxidation state of Cr are respectively

• A. 6 and +3
• B. 3 and zero
• C. 4 and+2
• D. 3 and +3

Answer 1

Answer: (A)

In $K_{3}Cr{(C_2{O}_4)}_3,$ chromium (Or) is attached by three divalent oxalate ligand hence the coordination number of Cr is 6. Let the oxidation state of Cr is $x$ in $K_{3}Cr{(C_2{O}_4)}_3$
$+3+x+3(-2)=0$
$3+x-6=0$
$x-3=0$
$x=+3$