In hydrogen atom, which one of the following transitions produce a spectrum line of maximum wavelength?

Question

In hydrogen atom, which one of the following transitions produce a spectrum line of maximum wavelength? (A) 6 to 5 (B) 5 to 2 (C) 4 to 1 (D) 2 to 1

Tardigrade Admin · Accepted Answer

For hydrogen atom spectrum, (1/λ)=R((1/nf2)-(1/ni2)) Therefore, for 6 to 5 ; λ=(30/ R ) for 5 to 2 ; λ=(10/3 R ) for 4 to 1 ; λ=(16/15 R ) for 2 to 1 ; λ=(4/3 R ) Hence, wavelength is maximum for transition 6 to 5.

Q. In hydrogen atom, which one of the following transitions produce a spectrum line of maximum wavelength?

6 to 5

5 to 2

4 to 1

2 to 1

For hydrogen atom spectrum,
$\frac{1}{λ} = R (\frac{1}{n _{f}^{2}} - \frac{1}{n _{i}^{2}})$
Therefore, for 6 to $5; λ = \frac{30}{R}$
for 5 to $2; λ = \frac{10}{3 R}$
for 4 to $1; λ = \frac{16}{15 R}$
for 2 to $1; λ = \frac{4}{3 R}$
Hence, wavelength is maximum for transition 6 to 5.

Q. In hydrogen atom, which one of the following transitions produce a spectrum line of maximum wavelength?

6 to 5

5 to 2

4 to 1

2 to 1

For hydrogen atom spectrum, λ1​=R(nf2​1​−ni2​1​) Therefore, for 6 to 5;λ=R30​ for 5 to 2;λ=3R10​ for 4 to 1;λ=15R16​ for 2 to 1;λ=3R4​ Hence, wavelength is maximum for transition 6 to 5.

For hydrogen atom spectrum,
$\frac{1}{λ} = R (\frac{1}{n _{f}^{2}} - \frac{1}{n _{i}^{2}})$
Therefore, for 6 to $5; λ = \frac{30}{R}$
for 5 to $2; λ = \frac{10}{3 R}$
for 4 to $1; λ = \frac{16}{15 R}$
for 2 to $1; λ = \frac{4}{3 R}$
Hence, wavelength is maximum for transition 6 to 5.