For hydrogen atom spectrum,
$\frac{1}{\lambda}=R\left(\frac{1}{n_f^2}-\frac{1}{n_i^2}\right)$
Therefore, for 6 to $5 ; \lambda=\frac{30}{ R }$
for 5 to $2 ; \lambda=\frac{10}{3 R }$
for 4 to $1 ; \lambda=\frac{16}{15 R }$
for 2 to $1 ; \lambda=\frac{4}{3 R }$
Hence, wavelength is maximum for transition 6 to 5.