In hydrogen atom, an electron in its ground state absorbs two times of the energy as if requires escaping (.13.6eV.) from the atom. The wavelength of the emitted electron will be

Question

In hydrogen atom, an electron in its ground state absorbs two times of the energy as if requires escaping (.13.6eV.) from the atom. The wavelength of the emitted electron will be (A) 1.34× 10- 10m (B) 2.34× 10- 10m (C) 3.34× 10- 10m (D) 4.44× 10- 10m

Tardigrade Admin · Accepted Answer

Energy absorbed by an atom =2× 13.6=27.2eV Energy consumed in escape =13.6eV Energy converted into K.E. =13.6× 1.6× 10- 19J λ =h / √2 m K E ∵ ( h=6.6× 10- 34kgm2s- 1 and m=9.1× 10- 31kg ) =(6.6 × 10- 34/√2 × 9.1 × 1 0- 31 × 13.6 × 1.6 × 1 0- 19) On solving =3.34× 10- 10m

Q. In hydrogen atom, an electron in its ground state absorbs two times of the energy as if requires escaping $(13.6 e V)$ from the atom. The wavelength of the emitted electron will be

$1.34 \times 1 0^{- 10} m$

$2.34 \times 1 0^{- 10} m$

$3.34 \times 1 0^{- 10} m$

$4.44 \times 1 0^{- 10} m$

Q. In hydrogen atom, an electron in its ground state absorbs two times of the energy as if requires escaping (13.6eV) from the atom. The wavelength of the emitted electron will be

1.34×10−10m

2.34×10−10m

3.34×10−10m

4.44×10−10m

Energy absorbed by an atom =2×13.6=27.2eV Energy consumed in escape =13.6eV Energy converted into K.E. =13.6×1.6×10−19J λ=h/2mKE​ ∵ ( h=6.6×10−34kgm2s−1 and m=9.1×10−31kg ) =2×9.1×10−31×13.6×1.6×10−19​6.6×10−34​ On solving =3.34×10−10m

Q. In hydrogen atom, an electron in its ground state absorbs two times of the energy as if requires escaping $(13.6 e V)$ from the atom. The wavelength of the emitted electron will be

$1.34 \times 1 0^{- 10} m$

$2.34 \times 1 0^{- 10} m$

$3.34 \times 1 0^{- 10} m$

$4.44 \times 1 0^{- 10} m$