In hydraulic press radii of connecting pipes, r1 and r2 are in ratio 1:2 . In order to lift a heavy mass M on larger piston, the small piston must be pressed through a minimum force f equal to -

Question

In hydraulic press radii of connecting pipes, r1 and r2 are in ratio 1:2 . In order to lift a heavy mass M on larger piston, the small piston must be pressed through a minimum force f equal to - <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-20oep0fmxbimyvoi.jpg" /> (A) Mg (B) (M g/2) (C) (M g/4) (D) (M g/5)

Tardigrade Admin · Accepted Answer

According to Pascal's principle and Hydraulic Lift concepts (f1/f2)=(A1/A2)=(r12/r22)=(1/4) f1=(1/4)Mg

Q. In hydraulic press radii of connecting pipes, $r_{1}$ and $r_{2}$ are in ratio $1 : 2$ . In order to lift a heavy mass $M$ on larger piston, the small piston must be pressed through a minimum force $f$ equal to -

$M g$

$\frac{M g}{2}$

$\frac{M g}{4}$

$\frac{M g}{5}$

According to Pascal's principle and Hydraulic Lift concepts
$\frac{f _{1}}{f _{2}} = \frac{A _{1}}{A _{2}} = \frac{r _{1}^{2}}{r _{2}^{2}} = \frac{1}{4}$
$f_{1} = \frac{1}{4} M g$

Q. In hydraulic press radii of connecting pipes, r1​ and r2​ are in ratio 1:2 . In order to lift a heavy mass M on larger piston, the small piston must be pressed through a minimum force f equal to -

Mg

2Mg​

4Mg​

5Mg​