In hexacyanomanganate (II) ion the Mn-atom assumes d2 s p2 -hybrid state. The number of unpaired electrons in the complex is:

Question

In hexacyanomanganate (II) ion the Mn-atom assumes d2 s p2 -hybrid state. The number of unpaired electrons in the complex is: (A) 2 (B) 3 (C) 0 (D) 1

Tardigrade Admin · Accepted Answer

Mn in Mn ( CN )64- has configuration: <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/5b44d81859636cb6bd9f2c1634ca9370-.png" />

Q. In hexacyanomanganate (II) ion the Mn-atom assumes $d^{2} s p^{2}$ -hybrid state. The number of unpaired electrons in the complex is:

2

3

0

1

$M n$ in $M n (CN)_{6}^{4 -}$ has configuration:

Q. In hexacyanomanganate (II) ion the Mn-atom assumes d2sp2 -hybrid state. The number of unpaired electrons in the complex is:

2

3

0

1

Mn in Mn(CN)64−​ has configuration:

Q. In hexacyanomanganate (II) ion the Mn-atom assumes $d^{2} s p^{2}$ -hybrid state. The number of unpaired electrons in the complex is:

$M n$ in $M n (CN)_{6}^{4 -}$ has configuration: