In Hell-Volhard-Zelinsky reaction, the carboxylic acids are halogenated at underlineA position by using underlineB and underlineC . Identify, A, B and C are

Question

In Hell-Volhard-Zelinsky reaction, the carboxylic acids are halogenated at underlineA position by using underlineB and underlineC . Identify, A, B and C are (A) A arrow α , B arrow NaOH , C arrow iodine (B) A arrow α , B arrow phosphorus, C arrow halogen (C) A arrow β, B arrow phosphorus, C arrow H2O (D) A arrow β, B arrow PCl5, C arrow NaOH

Tardigrade Admin · Accepted Answer

Correct answer is (b) A arrow α , B arrow phosphorus, C arrow halogen

Q. In Hell-Volhard-Zelinsky reaction, the carboxylic acids are halogenated at $\underline{A}$ position by using $\underline{B}$ and $\underline{C}$ . Identify, $A, B$ and $C$ are

$A \to α, B \to N a O H, C \to$ iodine

$A \to α, B \to$ phosphorus, $C \to$ halogen

$A \to β, B \to$ phosphorus, $C \to H_{2} O$

$A \to β, B \to PC l_{5}, C \to N a O H$

Correct answer is (b) $A \to α, B \to$ phosphorus, $C \to$ halogen

Q. In Hell-Volhard-Zelinsky reaction, the carboxylic acids are halogenated at A​ position by using B​ and C​ . Identify, A,B and C are

A→α,B→NaOH,C→ iodine

A→α,B→ phosphorus, C→ halogen

A→β,B→ phosphorus, C→H2​O

A→β,B→PCl5​,C→NaOH