Question

In Hell-Volhard-Zelinsky reaction, the carboxylic acids are halogenated at $\underline{A}$ position by using $\underline{B}$ and $\underline{C}$ . Identify, $A, B$ and $C$ are

• A. $A \rightarrow \alpha , B \rightarrow NaOH , C \rightarrow $ iodine
• B. $A \rightarrow \alpha , B \rightarrow $ phosphorus, $C \rightarrow $ halogen
• C. $A \rightarrow \beta, B \rightarrow $ phosphorus, $C \rightarrow H_2O$
• D. $A \rightarrow \beta, B \rightarrow PCl_5, C \rightarrow NaOH$

Answer 1

Answer: (B)

Correct answer is (b) $A \rightarrow \alpha , B \rightarrow $ phosphorus, $C \rightarrow $ halogen