In HCOO- , the two carbon-oxygen bonds are found to be of equal length. What is the reason for this?

Question

In HCOO- , the two carbon-oxygen bonds are found to be of equal length. What is the reason for this? (A) The anion is obtained by the removal of a proton from the acid molecule (B) Electronic orbitals of carbon atoms are hybridized (C) The C=O bond is weaker than C-O bond (D) The anion HCOO- has two resonating Structures

Tardigrade Admin · Accepted Answer

In HCOO- , the two carbon oxygen bonds are of equal length because the anion HCOO has two resonating structures.

Q. In $H CO O^{-}$ , the two carbon-oxygen bonds are found to be of equal length. What is the reason for this?

The anion is obtained by the removal of a proton from the acid molecule

Electronic orbitals of carbon atoms are hybridized

The $C = O$ bond is weaker than $C - O$ bond

The anion $H CO O^{-}$ has two resonating Structures

In $H CO O^{-}$ , the two carbon oxygen bonds are of equal length because the anion HCOO has two resonating structures.

Q. In HCOO− , the two carbon-oxygen bonds are found to be of equal length. What is the reason for this?

The anion is obtained by the removal of a proton from the acid molecule

Electronic orbitals of carbon atoms are hybridized

The C=O bond is weaker than C−O bond

The anion HCOO− has two resonating Structures

In HCOO− , the two carbon oxygen bonds are of equal length because the anion HCOO has two resonating structures.

Q. In $H CO O^{-}$ , the two carbon-oxygen bonds are found to be of equal length. What is the reason for this?

The $C = O$ bond is weaker than $C - O$ bond

The anion $H CO O^{-}$ has two resonating Structures

In $H CO O^{-}$ , the two carbon oxygen bonds are of equal length because the anion HCOO has two resonating structures.