In Haber process 30 L of dihydrogen and 30 L of dinitrogen were taken for reaction which yielded only 50 % of the expected product. What will be the composition of gaseous mixture under the aforesaid condition in the end?

Question

In Haber process 30 L of dihydrogen and 30 L of dinitrogen were taken for reaction which yielded only 50 % of the expected product. What will be the composition of gaseous mixture under the aforesaid condition in the end? (A) 20 L ammonia, 10 L nitrogen, 30 L hydrogen (B) 20 L ammonia, 25 L nitrogen, 15 L hydrogen (C) 20 L ammonia, 20 L nitrogen, 20 L hydrogen (D) 10 L ammonia, 25 L nitrogen, 15 L hydrogen

Tardigrade Admin · Accepted Answer

(d) N2 + 3H2 arrow 2NH3 10L1V 30L3V 20L2V As only 50% of the expected product is formed, hence only 10 L of NH3 is formed. Thus, for the production of 10 L of NH3 , 5 L of N2 and 15 L of H2 are used and composition of gaseous mixture under the aforesaid condition in the end is H2 = 30 - 15 = 15 L N2 = 30 - 5 = 25 L NH3 = 10 L

Q. In Haber process 30L of dihydrogen and 30L of dinitrogen were taken for reaction which yielded only 50% of the expected product. What will be the composition of gaseous mixture under the aforesaid condition in the end?

20 L ammonia, 10 L nitrogen, 30 L hydrogen

20 L ammonia, 25 L nitrogen, 15 L hydrogen

20 L ammonia, 20 L nitrogen, 20 L hydrogen

10 L ammonia, 25 L nitrogen, 15 L hydrogen

Q. In Haber process $30 L$ of dihydrogen and $30 L$ of dinitrogen were taken for reaction which yielded only $50%$ of the expected product. What will be the composition of gaseous mixture under the aforesaid condition in the end?