Question

In $H{e}_2$ the electrons in bonding and anti-bonding orbitals are

• A. 2, 2
• B. 4, 2
• C. 4, 0
• D. 2, 4

Answer 1

Answer: (A)

Number of electron in $H{e}_2=4$
$MO$ configuration of $H{e}_2=\sigma 1s^2,{\sigma }^{\ast }1s^2$
Here, $N_b$ (bonding electrons) $=2N_a$ (antibonding electrons) $=2$