Question

In graphite and diamond, the percentage of p-characters of the hybrid orbitals in hybridisation are respectively :

• A. 33 and 25
• B. 33 and 75
• C. 50 and 75
• D. 67 and 75

Answer 1

Answer: (D)

In graphite, each carbon is $s{p}^2$ hybridised. Therefore, percentage of $p$ -character can be calculated as

$\%\text{ of }p\text{ character }=\frac{2}{3}\times 100=66.66\%$

In diamond, each carbon is $s{p}^3$ hybridised. Therefore, percentage of $p$ -character can be calculated as

$\%\text{ of }p\text{ character }=\frac{3}{4}\times 100=75\%$