In figure, displacement-time (x-t) graph given below, the average velocity between time t=5 s and t=7 s is

Question

In figure, displacement-time (x-t) graph given below, the average velocity between time t=5 s and t=7 s is (A) 8 ms -1 (B) 8.7 ms -1 (C) 7.8 ms -1 (D) 13.7 ms -1

Tardigrade Admin · Accepted Answer

Given, x2=27.4 m , x1=10 m , t2=7 s and t1=5 s. Average velocity between 5 s and 7 s is barv=(x2-x1/t2-t1)=(27.4-10/7-5)=(17.4/2)=8.7 ms -1

Q. In figure, displacement-time $(x - t)$ graph given below, the average velocity between time $t = 5 s$ and $t = 7 s$ is

$8 m s^{- 1}$

$8.7 m s^{- 1}$

$7.8 m s^{- 1}$

$13.7 m s^{- 1}$

Given, $x_{2} = 27.4 m, x_{1} = 10 m, t_{2} = 7 s$ and $t_{1} = 5 s$ . Average velocity between $5 s$ and $7 s$ is
$\overset{v}{ˉ} = \frac{x _{2} - x _{1}}{t _{2} - t _{1}} = \frac{27.4 - 10}{7 - 5} = \frac{17.4}{2} = 8.7 m s^{- 1}$

Q. In figure, displacement-time (x−t) graph given below, the average velocity between time t=5s and t=7s is

8ms−1

8.7ms−1

7.8ms−1

13.7ms−1