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Q.
In figure, displacement-time $(x-t)$ graph given below,
the average velocity between time $t=5 s$ and $t=7 s$ is
Motion in a Straight Line
Solution:
Given, $x_{2}=27.4 m , x_{1}=10 m , t_{2}=7 s$ and $t_{1}=5 s$. Average velocity between $5 s$ and $7 s$ is
$\bar{v}=\frac{x_{2}-x_{1}}{t_{2}-t_{1}}=\frac{27.4-10}{7-5}=\frac{17.4}{2}=8.7 ms ^{-1}$
