In electromagnetic induction, the induced charge in a coil is independent of

Question

In electromagnetic induction, the induced charge in a coil is independent of (A) Change in the flux (B) Time (C) Resistance in the circuit (D) None of the above

Tardigrade Admin · Accepted Answer

We know that e=(d φ/d t) But e=i R and i=(d q/d t) ⇒ (d q/d t)=(e/R) ⇒ d q=(d φ/R)

Q. In electromagnetic induction, the induced charge in a coil is independent of

Change in the flux

Time

Resistance in the circuit

None of the above

We know that $e = \frac{d ϕ}{d t}$
But $e = i R$ and $i = \frac{d q}{d t}$
$\Rightarrow \frac{d q}{d t} = \frac{e}{R}$
$\Rightarrow d q = \frac{d ϕ}{R}$

Q. In electromagnetic induction, the induced charge in a coil is independent of

Change in the flux

Time

Resistance in the circuit

None of the above

We know that e=dtdϕ​ But e=iR and i=dtdq​ ⇒dtdq​=Re​ ⇒dq=Rdϕ​

We know that $e = \frac{d ϕ}{d t}$
But $e = i R$ and $i = \frac{d q}{d t}$
$\Rightarrow \frac{d q}{d t} = \frac{e}{R}$
$\Rightarrow d q = \frac{d ϕ}{R}$