In Dumas method 0.5 g of an organic compound containing nitrogen gave 112 ml of nitrogen at S.T.P. The percentage of nitrogen in the given compound is:

Question

In Dumas method 0.5 g of an organic compound containing nitrogen gave 112 ml of nitrogen at S.T.P. The percentage of nitrogen in the given compound is: (A) 28 (B) 38 (C) 18 (D) 48

Tardigrade Admin · Accepted Answer

% N =(28/22400) × ( text Vol. of N 2 text at STP ( ml )/ text wt. of org. comp ) × 100

Q. In Dumas method $0.5 g$ of an organic compound containing nitrogen gave $112 m l$ of nitrogen at S.T.P. The percentage of nitrogen in the given compound is:

$28$

$38$

$18$

$48$

$% N = \frac{28}{22400} \times \frac{Vol. of N _{2} at STP ( m l )}{wt. of org. comp} \times 100$

Q. In Dumas method 0.5g of an organic compound containing nitrogen gave 112ml of nitrogen at S.T.P. The percentage of nitrogen in the given compound is:

28

38

18

48