In Doppler effect, when a source moves towards a stationary observer, the apparent increase in frequency is due to

Question

In Doppler effect, when a source moves towards a stationary observer, the apparent increase in frequency is due to (A) increase in wavelength of sound received by observer (B) decrease in wavelength of sound received by observer (C) increase in number of waves received by observer in one second (D) decrease in number of waves received by observer in one second

Tardigrade Admin · Accepted Answer

Change of frequency due to the Doppler effect is :

\overset{n}{ˉ} = n (\frac{v}{v - v _{s}}) .

So,

\overset{n}{ˉ} > n

, So increase in the frequency.
Now, frequency is inversely proportional to the wavelength,
so in this case the wavelength will decrease.

Q. In Doppler effect, when a source moves towards a stationary observer, the apparent increase in frequency is due to

increase in wavelength of sound received by observer

decrease in wavelength of sound received by observer

increase in number of waves received by observer in one second

decrease in number of waves received by observer in one second

Change of frequency due to the Doppler effect is : nˉ=n(v−vs​v​). So, nˉ>n, So increase in the frequency. Now, frequency is inversely proportional to the wavelength, so in this case the wavelength will decrease.

Change of frequency due to the Doppler effect is :
$\overset{n}{ˉ} = n (\frac{v}{v - v _{s}}) .$
So, $\overset{n}{ˉ} > n$ , So increase in the frequency.
Now, frequency is inversely proportional to the wavelength,
so in this case the wavelength will decrease.