in Define an=(12+22+32+ ldots .+n2)n and bn=nn(n !)2 then

Question

in Define an=(12+22+32+ ldots .+n2)n and bn=nn(n !)2 then (A) an< bn ∀ n>1 (B) an >bn ∀ n >5 (C) a n = b n ∀ n (D) None of these

Tardigrade Admin · Accepted Answer

Correct answer is (b) an >bn ∀ n >5

Q. in Define $a_{n} = (1^{2} + 2^{2} + 3^{2} + \dots . + n^{2})^{n}$ and $b_{n} = n^{n} (n!)^{2}$ then