In copper voltameter, mass deposited in 30 s is m gram. If the time-current graph is as shown in figure, ECE of copper is

Question

In copper voltameter, mass deposited in 30 s is m gram. If the time-current graph is as shown in figure, ECE of copper is (A) m (B) m/2 (C) 0.6m (D) 0.1m

Tardigrade Admin · Accepted Answer

z =m / I t, From graph, It = Area O A B C =(1/2)(10+30) × (100/1000)=2 ∴ z=m / 2=0.5 m

Q. In copper voltameter, mass deposited in $30 s$ is $m$ gram. If the time-current graph is as shown in figure, ECE of copper is

m

m/2

0.6m

0.1m

$z = m / I t$ ,
From graph, It $=$ Area $O A BC$
$= \frac{1}{2} (10 + 30) \times \frac{100}{1000} = 2$
$∴ z = m /2 = 0.5 m$

Q. In copper voltameter, mass deposited in 30s is m gram. If the time-current graph is as shown in figure, ECE of copper is

m

m/2

0.6m

0.1m

z=m/It, From graph, It = Area OABC =21​(10+30)×1000100​=2 ∴z=m/2=0.5m

Q. In copper voltameter, mass deposited in $30 s$ is $m$ gram. If the time-current graph is as shown in figure, ECE of copper is

$z = m / I t$ ,
From graph, It $=$ Area $O A BC$
$= \frac{1}{2} (10 + 30) \times \frac{100}{1000} = 2$
$∴ z = m /2 = 0.5 m$