In common-emitter transistor amplifier, the phase difference between output voltage and input voltage is:

Question

In common-emitter transistor amplifier, the phase difference between output voltage and input voltage is: (A)  0°  (B)  180°  (C)  90°  (D)  45°

Tardigrade Admin · Accepted Answer

In common-emitter configuration of a transistor amplifier, the input signal fed to it is inverted and amplified at the output. Thus, phase difference between input and output signals is 180° .

Q. In common-emitter transistor amplifier, the phase difference between output voltage and input voltage is:

$0^{\circ}$

$18 0^{\circ}$

$9 0^{\circ}$

$4 5^{\circ}$

In common-emitter configuration of a transistor amplifier, the input signal fed to it is inverted and amplified at the output. Thus, phase difference between input and output signals is $18 0^{\circ}$ .