In [Co(NH3)6]CI3, the number of covalent bonds is

Question

In [Co(NH3)6]CI3, the number of covalent bonds is (A) 3 (B) 6 (C) 9 (D) 18

Tardigrade Admin · Accepted Answer

M - L bond is coordinate. In ligand itself, NH3, three hydrogens are covalently linked to nitrogen atoms. Hence, total number of covalent bonds= 6 × 3 = 18

Q. In $[C o (N H_{3})_{6}] C I_{3}$ , the number of covalent bonds is

3

6

9

18

$M - L$ bond is coordinate. In ligand itself, $N H_{3}$ , three hydrogens are covalently linked to nitrogen atoms. Hence, total number of covalent bonds $= 6 \times 3 = 18$

Q. In [Co(NH3​)6​]CI3​, the number of covalent bonds is

3

6

9

18

M−L bond is coordinate. In ligand itself, NH3​, three hydrogens are covalently linked to nitrogen atoms. Hence, total number of covalent bonds=6×3=18

Q. In $[C o (N H_{3})_{6}] C I_{3}$ , the number of covalent bonds is

$M - L$ bond is coordinate. In ligand itself, $N H_{3}$ , three hydrogens are covalently linked to nitrogen atoms. Hence, total number of covalent bonds $= 6 \times 3 = 18$