In circular motion if v is velocity vector, α is acceleration vector, r is instantaneous position vector, and p is momentum vector and ω is angular velocity of particle. Then

Question

In circular motion if v is velocity vector, α is acceleration vector, r is instantaneous position vector, and p is momentum vector and ω is angular velocity of particle. Then (A) v,ω and r are mutually perpendicular (B) P,v and ω are mutually perpendicular (C) r.v=0 and r.ω=0 (D) both 1 and 3

Tardigrade Admin · Accepted Answer

Correct answer is (d) both 1 and 3

Q. In circular motion if $v$ is velocity vector, $α$ is acceleration vector, $r$ is instantaneous position vector, and $p$ is momentum vector and $ω$ is angular velocity of particle. Then

$v, ω an d r$ are mutually perpendicular

$P, v an d ω$ are mutually perpendicular

$r . v = 0 an d r . ω = 0$

both 1 and 3

Correct answer is (d) both 1 and 3

Q. In circular motion if v is velocity vector, α is acceleration vector, r is instantaneous position vector, and p​ is momentum vector and ω is angular velocity of particle. Then

v,ωandr are mutually perpendicular

P,vandω are mutually perpendicular

r.v=0andr.ω=0

both 1 and 3

Correct answer is (d) both 1 and 3

Q. In circular motion if $v$ is velocity vector, $α$ is acceleration vector, $r$ is instantaneous position vector, and $p$ is momentum vector and $ω$ is angular velocity of particle. Then

$v, ω an d r$ are mutually perpendicular

$P, v an d ω$ are mutually perpendicular

$r . v = 0 an d r . ω = 0$