Question

In case of photoelectric effect, slope of $V_0$ vs $\nu$ curve is (where $V_0$ - stopping potential, $\nu =$ subjected frequency)

• A. $e$
• B. $\frac{h}{e}$
• C. $\varphi$
• D. $h$

Answer 1

Answer: (B)

$h\nu ={\omega }_0+e{V}_0\dots (1)$
${\omega }_0=$ threshold energy
$h\nu =h{\nu }_0+e{V}_0$
$V_0=\frac{h{\nu }_0}{e}-\frac{h{\nu }_0}{e}\dots (2)$
$\nu =$ subjected frequency
${\nu }_0=$ threshold frequency
Comparing equation (2) with straight line equation:
$y=mx+c$
Slope of ${\nu }_0$ v/s $\nu$ curve $=\frac{h}{e}$