Question

In Carius method of estimation of halogen, $0.172g$ of an organic compound showed presence of $0.08g$ of bromine. Which of these is the correct structure of the compound :

• A.
• B. $H_{3}C-C{H}_2-Br$
• C.
• D. $H_{3}C-Br$

Answer 1

Answer: (A)

In Carius method

mass of organic compound $=0.172gm$

mass of Bromine $=0.08gm$

Hence $\%$ of Bromine $=\frac{0.08}{0.172}\times 100$

$=46.51\%$

(1)

$[\%Br=\frac{80}{172}\times 100]=46.51\%$

(2) $C{H}_{3}C{H}_{2}Br{C}_2{H}_{5}Br\%Br=\frac{80}{109}\times 100=73.33\%$



(4) $C{H}_{3}Br$