Q. In $C H_{2} C l_{2}$ , the oxidation number of $C$ is

1885 247 Punjab PMETPunjab PMET 1999 Report Error

A

$+ 2$

B

$- 4$

C

$0$

D

$+ 4$

Solution:

Let $x$ be the oxidation number of $C$ in $C H_{2} C l_{2}$ $x + 2 \times 1 + 2 \times (- 1) = 0$ $x = 0$