In bromination of Propyne, with Bromine 1, 1,2, 2-tetrabromopropane is obtained in 27 % yield. The amount of 1,1,2,2 tetrabromopropane obtained from 1 g of Bromine in this reaction is × 10-1 g. (Nearest integer) (Molar Mass: Bromine =80 g / mol )

Question

In bromination of Propyne, with Bromine 1, 1,2, 2-tetrabromopropane is obtained in 27 % yield. The amount of 1,1,2,2 tetrabromopropane obtained from 1 g of Bromine in this reaction is × 10-1 g. (Nearest integer) (Molar Mass: Bromine =80 g / mol ) (A)  (B)  (C)  (D)

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<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/3c35e7f61eee1ea1170c6f33ae911e53-.png" /> =(1/160) × (1/2) × 360 × 0.27 =0.30375 =3.0375 × 10-1 =3

Q. In bromination of Propyne, with Bromine 1, 1,2, 2-tetrabromopropane is obtained in $27%$ yield. The amount of $1, 1, 2, 2$ tetrabromopropane obtained from $1 g$ of Bromine in this reaction is ___ $\times 1 0^{- 1} g$ . (Nearest integer)
(Molar Mass : Bromine $= 80 g / m o l)$

$= \frac{1}{160} \times \frac{1}{2} \times 360 \times 0.27$
$= 0.30375$
$= 3.0375 \times 1 0^{- 1}$
$= 3$

Q. In bromination of Propyne, with Bromine 1, 1,2, 2-tetrabromopropane is obtained in 27% yield. The amount of 1,1,2,2 tetrabromopropane obtained from 1g of Bromine in this reaction is ___×10−1g. (Nearest integer) (Molar Mass : Bromine =80g/mol)

=1601​×21​×360×0.27 =0.30375 =3.0375×10−1 =3

Q. In bromination of Propyne, with Bromine 1, 1,2, 2-tetrabromopropane is obtained in $27%$ yield. The amount of $1, 1, 2, 2$ tetrabromopropane obtained from $1 g$ of Bromine in this reaction is ___ $\times 1 0^{- 1} g$ . (Nearest integer)
(Molar Mass : Bromine $= 80 g / m o l)$

$= \frac{1}{160} \times \frac{1}{2} \times 360 \times 0.27$
$= 0.30375$
$= 3.0375 \times 1 0^{- 1}$
$= 3$