In Bohr series of lines of hydrogen spectrum, third line from the red end corresponds to which one of the following inner orbit jumps of electron for Bohr orbit in atom of hydrogen:

Question

In Bohr series of lines of hydrogen spectrum, third line from the red end corresponds to which one of the following inner orbit jumps of electron for Bohr orbit in atom of hydrogen: (A) 4 → 1 (B) 2 → 5 (C) 3→2 (D) 5 → 2

Tardigrade Admin · Accepted Answer

The emission is in visible (VIBGYOR) region. Thus Balmer series i.e., either (c) or (d). In (c) only one emission. The third line will be in the jump from 5 to 2.

Q. In Bohr series of lines of hydrogen spectrum, third line from the red end corresponds to which one of the following inner orbit jumps of electron for Bohr orbit in atom of hydrogen:

$4 \to 1$

$2 \to 5$

$3 \to 2$

$5 \to 2$

The emission is in visible (VIBGYOR) region. Thus Balmer series i.e., either (c) or (d). In (c) only one emission. The third line will be in the jump from $5$ to $2$ .