In Bohr’s model, the atomic radius of the first orbit is r0 . The radius of the third orbit, is

Question

In Bohr’s model, the atomic radius of the first orbit is r0 . The radius of the third orbit, is (A) 9 r0 (B) 3 r0 (C)  r0 (D) (r0/3)

Tardigrade Admin · Accepted Answer

Here: Radius of first orbit =r0 The radius of n the orbit is given by, rn=(ε0 h2/π m Ze2) × n2 propto n2 Hence, (r1/r2)=((n1/n2))2 =(1/9) or r3=9 r1=9 r0 (where r3 is the radius of 3rd orbit)

Q. In Bohr’s model, the atomic radius of the first orbit is $r_{0}$ . The radius of the third orbit, is

$9 r_{0}$

$3 r_{0}$

$r_{0}$

$\frac{r _{0}}{3}$

Q. In Bohr’s model, the atomic radius of the first orbit is r0​ . The radius of the third orbit, is

9r0​

3r0​

r0​

3r0​​

Here : Radius of first orbit =r0​ The radius of n the orbit is given by, rn​=πmZe2​ε0​h2​×n2∝n2 Hence, r2​r1​​=(n2​n1​​)2 =91​ or r3​=9r1​=9r0​ (where r3​ is the radius of 3rd orbit)

Q. In Bohr’s model, the atomic radius of the first orbit is $r_{0}$ . The radius of the third orbit, is

$9 r_{0}$

$3 r_{0}$

$r_{0}$

$\frac{r _{0}}{3}$