In basic medium CrO 42- oxidises S 2 O 32- to form SO 42- and itself changes into Cr ( OH )4-. The volume of 0.154 M CrO 42- required to react with 40 mL of 0.25 M S 2 O 32- is mL (Rounded-off to the nearest integer)

Question

In basic medium CrO 42- oxidises S 2 O 32- to form SO 42- and itself changes into Cr ( OH )4-. The volume of 0.154 M CrO 42- required to react with 40 mL of 0.25 M S 2 O 32- is mL (Rounded-off to the nearest integer) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

overset+6CrO 42-+ overset+2S 2 O 32- → overset+6S O 42-+ overset+3Cr ( OH )4 gm equi. of CrO 42-= S 2 O 32- 0.154 × 3 × v =0.25 × 40 × 8 v =173.16=173 ml

Q. In basic medium $C r O_{4}^{2 -}$ oxidises $S_{2} O_{3}^{2 -}$ to form $S O_{4}^{2 -}$ and itself changes into $C r (O H)_{4}^{-}$ . The volume of $0.154 MC r O_{4}^{2 -}$ required to react with $40 m L$ of $0.25 M S_{2} O_{3}^{2 -}$ is ____ $m L$
(Rounded-off to the nearest integer)

$C + 6 r O_{4}^{2 -} + S + 2_{2} O_{3}^{2 -} \to S + 6 O_{4}^{2 -} + C + 3 r (O H)_{4}$

gm equi. of $C r O_{4}^{2 -} = S_{2} O_{3}^{2 -}$

$0.154 \times 3 \times v = 0.25 \times 40 \times 8$

$v = 173.16 = 173 m l$

Q. In basic medium CrO42−​ oxidises S2​O32−​ to form SO42−​ and itself changes into Cr(OH)4−​. The volume of 0.154MCrO42−​ required to react with 40mL of 0.25MS2​O32−​ is ____mL (Rounded-off to the nearest integer)

C+6rO42−​+S+22​O32−​→S+6O42−​+C+3r(OH)4​ gm equi. of CrO42−​=S2​O32−​ 0.154×3×v=0.25×40×8 v=173.16=173ml

Q. In basic medium $C r O_{4}^{2 -}$ oxidises $S_{2} O_{3}^{2 -}$ to form $S O_{4}^{2 -}$ and itself changes into $C r (O H)_{4}^{-}$ . The volume of $0.154 MC r O_{4}^{2 -}$ required to react with $40 m L$ of $0.25 M S_{2} O_{3}^{2 -}$ is ____ $m L$
(Rounded-off to the nearest integer)

$C + 6 r O_{4}^{2 -} + S + 2_{2} O_{3}^{2 -} \to S + 6 O_{4}^{2 -} + C + 3 r (O H)_{4}$

gm equi. of $C r O_{4}^{2 -} = S_{2} O_{3}^{2 -}$

$0.154 \times 3 \times v = 0.25 \times 40 \times 8$

$v = 173.16 = 173 m l$