1. Tardigrade
  2. Question
  3. Chemistry
  4. In basic medium CrO 42- oxidises S 2 O 32- to form SO 42- and itself changes into Cr ( OH )4-. The volume of 0.154 M CrO 42- required to react with 40 mL of 0.25 M S 2 O 32- is mL (Rounded-off to the nearest integer)

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. In basic medium $CrO _{4}^{2-}$ oxidises $S _{2} O _{3}^{2-}$ to form $SO _{4}^{2-}$ and itself changes into $Cr ( OH )_{4}^{-}$. The volume of $0.154 M CrO _{4}^{2-}$ required to react with $40 mL$ of $0.25 M S _{2} O _{3}^{2-}$ is ____$mL$
(Rounded-off to the nearest integer)

JEE MainJEE Main 2021Redox Reactions

Solution:

$\overset{+6}{C}rO _{4}^{2-}+ \overset{+2}{S} _{2} O _{3}^{2-} \to \overset{+6}{S} O _{4}^{2-}+ \overset{+3}{C}r ( OH )_{4}$

gm equi. of $CrO _{4}^{2-}= S _{2} O _{3}^{2-}$

$ 0.154 \times 3 \times v =0.25 \times 40 \times 8 $

$ v =173.16=173 \,ml $