Question

In $B{r}_3{O}_8$ compound, oxidation number of bromine is

• A. $16/13$
• B. $26/3$
• C. $24/3$
• D. $16/3$

Answer 1

Answer: (D)

$B{r}_3{O}_8$ Let oxidation number of $Br$ is $x.$
$\therefore$ $3x+8(-2)=0$ or $3x=16\Rightarrow x=\frac{16}{3}$