In an oxidation reduction reaction, dichromate (Cr2O72-) ion is reduced to Cr3+ ion. The equivalent weight of K2Cr2O7 in this reaction is molecular weight

Question

In an oxidation reduction reaction, dichromate (Cr2O72-) ion is reduced to Cr3+ ion. The equivalent weight of K2Cr2O7 in this reaction is molecular weight (A)  (molecular weight/3)  (B)  (molecular weight/6)  (C)  (molecular weight/1)  (D)  (molecular weight/2)

Tardigrade Admin · Accepted Answer

overset+6 mathopK2Cr2O7 +4H2SO4 xrightarrowK2SO4+ overset+3 mathopCr2 (SO4)3 +4H2+3[O] Equivalent weight =(Molecular weight/ beginalign Change in oxidation number of atoms present in one molecular endalign) ∴ Equivalent weight =(Molecular weight/2× 3) =(Molecular weight/6)

Q. In an oxidation reduction reaction, dichromate $(C r_{2} O_{7}^{2 -})$ ion is reduced to $C r^{3 +}$ ion. The equivalent weight of $K_{2} C r_{2} O_{7}$ in this reaction is molecular weight

$\frac{m o l ec u l a r w e i g h t}{3}$

$\frac{m o l ec u l a r w e i g h t}{6}$

$\frac{m o l ec u l a r w e i g h t}{1}$

$\frac{m o l ec u l a r w e i g h t}{2}$

Q. In an oxidation reduction reaction, dichromate (Cr2​O72−​) ion is reduced to Cr3+ ion. The equivalent weight of K2​Cr2​O7​ in this reaction is molecular weight

3molecularweight​

6molecularweight​

1molecularweight​

2molecularweight​

K2​Cr2​O7​+6​+4H2​SO4​​K2​SO4​+Cr2​+3​(SO4​)3​ +4H2​+3[O] Equivalent weight =​Changeinoxidationnumberofatomspresentinonemolecular​Molecularweight​ ∴ Equivalent weight =2×3Molecularweight​ =6Molecularweight​

Q. In an oxidation reduction reaction, dichromate $(C r_{2} O_{7}^{2 -})$ ion is reduced to $C r^{3 +}$ ion. The equivalent weight of $K_{2} C r_{2} O_{7}$ in this reaction is molecular weight

$\frac{m o l ec u l a r w e i g h t}{3}$

$\frac{m o l ec u l a r w e i g h t}{6}$

$\frac{m o l ec u l a r w e i g h t}{1}$

$\frac{m o l ec u l a r w e i g h t}{2}$