In an oscillating LC circuit, L =3.00 mH and C =2.70 μ F . At t =0 the charge on the capacitor is zero and the current is 2.00 A. The maximum charge that will appear on the capacitor will be

Question

In an oscillating LC circuit, L =3.00 mH and C =2.70 μ F . At t =0 the charge on the capacitor is zero and the current is 2.00 A. The maximum charge that will appear on the capacitor will be (A) 1.8 × 10-5 C (B) 18 × 10-5 C (C) 9 × 10-5 C (D) 90 × 10-5 C

Tardigrade Admin · Accepted Answer

( Q 2/2 C )=( LI 2/2) ( Q 2/2 × 2.7 × 10-6) =(3 × 10-3 × 42/2) Q 2=12 × 10-3 × 2.7 × 10-6 =32.4 × 10-9 Q =18 × 10-5 C

Q. In an oscillating LC circuit, $L = 3.00 m H$ and $C = 2.70 μ F .$ At $t = 0$ the charge on the capacitor is zero and the current is $2.00 A$ . The maximum charge that will appear on the capacitor will be

$1.8 \times 1 0^{- 5} C$

$18 \times 1 0^{- 5} C$

$9 \times 1 0^{- 5} C$

$90 \times 1 0^{- 5} C$

$\frac{Q ^{2}}{2 C} = \frac{L I ^{2}}{2}$
$\frac{Q ^{2}}{2 \times 2.7 \times 1 0 ^{- 6}} = \frac{3 \times 1 0 ^{- 3} \times 4 ^{2}}{2}$
$Q^{2} = 12 \times 1 0^{- 3} \times 2.7 \times 1 0^{- 6}$
$= 32.4 \times 1 0^{- 9}$
$Q = 18 \times 1 0^{- 5} C$

Q. In an oscillating LC circuit, L=3.00mH and C=2.70μF. At t=0 the charge on the capacitor is zero and the current is 2.00A. The maximum charge that will appear on the capacitor will be

1.8×10−5C

18×10−5C

9×10−5C

90×10−5C