In an L-C-R series circuit, the values of R, XL and XC are 120 Ω, 180 Ω and 130 Ω, what is the impedance of the circuit?

Question

In an L-C-R series circuit, the values of R, XL and XC are 120 Ω, 180 Ω and 130 Ω, what is the impedance of the circuit? (A) 120 Ω (B) 130 Ω (C) 180 Ω (D) 330 Ω

Tardigrade Admin · Accepted Answer

Given, R=120 Ω XL=180 Ω, XC=130 Ω The impedance of L-C-R circuit Z=√R2+(XL-XC)2 Z=√(120)2+(180-130)2=130 Ω

Q. In an $L - C - R$ series circuit, the values of $R, X_{L}$ and $X_{C}$ are $120 Ω, 180 Ω$ and $130 Ω$ , what is the impedance of the circuit?

$120 Ω$

$130 Ω$

$180 Ω$

$330 Ω$

Given, $R = 120 Ω$
$X_{L} = 180 Ω, X_{C} = 130 Ω$
The impedance of $L - C - R$ circuit
$Z = R^{2} + (X_{L} - X_{C})^{2}$
$Z = (120)^{2} + (180 - 130)^{2} = 130 Ω$

Q. In an L−C−R series circuit, the values of R,XL​ and XC​ are 120Ω,180Ω and 130Ω, what is the impedance of the circuit?

120Ω

130Ω

180Ω

330Ω