Question

In an isobaric process, the work done by a diatomic gas is $10J$, the heat given to the gas will be :

• A. 35 J
• B. 30 J
• C. 45 J
• D. 60 J

Answer 1

Answer: (A)

For constant pressure process
$\frac{W}{Q}=\frac{nR\Delta T}{n{C}_p\Delta T}=\frac{nR\Delta T}{n\left(\frac{f}{2}+1\right)R\Delta T}=\frac{1}{f/2+1}$
$\frac{W}{Q}=\frac{1}{\left(\frac{5}{2}+1\right)}=\frac{2}{7}\Rightarrow Q=\frac{7}{2}W=\frac{7}{2}\times 10=35J$