In an irreversible process taking place at constant T and P and in which only pressure-volume work is being done, the change in Gibbs free energy (dG) and change in entropy (dS), satisfy the criteria:

Question

In an irreversible process taking place at constant T and P and in which only pressure-volume work is being done, the change in Gibbs free energy (dG) and change in entropy (dS), satisfy the criteria: (A) (d S)V, E<0,(d G)T, P< 0 (B) (d S)V, E>0,(d G)T, p< 0 (C) (d S)V, E=0,(d G)T, p = 0 (D) (d S)V, E=0,(d G)T, p > 0

Tardigrade Admin · Accepted Answer

An irreversible process ⇒ spontaneous process ⇒ (d S)v E (change in entropy) =+ ve > 0 ⇒ (d G)T, p (change in Gibbs free energy) - ve ⇒ < 0

Q. In an irreversible process taking place at constant $T$ and $P$ and in which only pressure-volume work is being done, the change in Gibbs free energy (dG) and change in entropy (dS), satisfy the criteria:

$(d S)_{V, E} < 0, (d G)_{T, P} < 0$

$(d S)_{V, E} > 0, (d G)_{T, p} < 0$

$(d S)_{V, E} = 0, (d G)_{T, p} = 0$

$(d S)_{V, E} = 0, (d G)_{T, p} > 0$

An irreversible process

$\Rightarrow$ spontaneous process

$\Rightarrow (d S)_{v E}$ (change in entropy) $= + v e > 0$

$\Rightarrow (d G)_{T, p}$ (change in Gibbs free energy)

$- v e \Rightarrow< 0$

Q. In an irreversible process taking place at constant T and P and in which only pressure-volume work is being done, the change in Gibbs free energy (dG) and change in entropy (dS), satisfy the criteria:

(dS)V,E​<0,(dG)T,P​<0

(dS)V,E​>0,(dG)T,p​<0

(dS)V,E​=0,(dG)T,p​=0

(dS)V,E​=0,(dG)T,p​>0