In an irreversible process taking place at constant T and P and in which only pressure-volume work is being done, the change in Gibbs free energy (dG) and change in entropy (dS) , satisfy the criteria

Question

In an irreversible process taking place at constant T and P and in which only pressure-volume work is being done, the change in Gibbs free energy (dG) and change in entropy (dS) , satisfy the criteria (A) (dS)V, E<0, (dG)T, P<0 (B) (dS)V, E>0, (dG)T, P<0 (C) (dS)V, E=0, (dG)T, P=0 (D) (dS)V, E=0, (dG)T, P>0

Tardigrade Admin · Accepted Answer

An irreversible process ⇒ spontaneous process ⇒ (dS)VE (change in entropy) =+ve>0 ⇒ (dG)T, P (change in Gibbs free energy) -ve⇒ <0

Q. In an irreversible process taking place at constant $T$ and $P$ and in which only pressure-volume work is being done, the change in Gibbs free energy $(d G)$ and change in entropy $(d S)$ , satisfy the criteria

$(d S)_{V, E} < 0, (d G)_{T, P} < 0$

$(d S)_{V, E} > 0, (d G)_{T, P} < 0$

$(d S)_{V, E} = 0, (d G)_{T, P} = 0$

$(d S)_{V, E} = 0, (d G)_{T, P} > 0$

An irreversible process $\Rightarrow$ spontaneous process $\Rightarrow (d S)_{V E}$ (change in entropy) $= + v e > 0$ $\Rightarrow$ $(d G)_{T, P}$ (change in Gibbs free energy) $- v e \Rightarrow < 0$

Q. In an irreversible process taking place at constant T and P and in which only pressure-volume work is being done, the change in Gibbs free energy (dG) and change in entropy (dS) , satisfy the criteria

(dS)V,E​<0,(dG)T,P​<0

(dS)V,E​>0,(dG)T,P​<0

(dS)V,E​=0,(dG)T,P​=0

(dS)V,E​=0,(dG)T,P​>0