In an intrinsic semiconductor, the density of conduction electrons is 7.07 × 1015 m -3 . When it is doped with indium, the density of holes becomes 5 × 1022 m -3. Find the density of conduction electrons in doped semiconductor

Question

In an intrinsic semiconductor, the density of conduction electrons is 7.07 × 1015 m -3 . When it is doped with indium, the density of holes becomes 5 × 1022 m -3. Find the density of conduction electrons in doped semiconductor (A) Zero (B) 1 × 109 m -3 (C) 7 × 1015 m -3 (D) 5 × 1022 m -3

Tardigrade Admin · Accepted Answer

ne .nh=ni2 and ne=nh=ni initially or ni=7.07 × 1015 m -3 ne=((7.07 × 1015)2/5 × 1022) on ne ≈ 1 × 109 m -3

Q. In an intrinsic semiconductor, the density of conduction electrons is $7.07 \times 1 0^{15} m^{- 3} .$ When it is doped with indium, the density of holes becomes $5 \times 1 0^{22} m^{- 3}$ . Find the density of conduction electrons in doped semiconductor

Zero

$1 \times 1 0^{9} m^{- 3}$

$7 \times 1 0^{15} m^{- 3}$

$5 \times 1 0^{22} m^{- 3}$

$n_{e} . n_{h} = n_{i}^{2}$
and $n_{e} = n_{h} = n_{i}$ initially
or $n_{i} = 7.07 \times 1 0^{15} m^{- 3}$
$n_{e} = \frac{( 7.07 \times 1 0 ^{15} ) ^{2}}{5 \times 1 0 ^{22}}$
on $n_{e} \approx 1 \times 1 0^{9} m^{- 3}$

Q. In an intrinsic semiconductor, the density of conduction electrons is 7.07×1015m−3. When it is doped with indium, the density of holes becomes 5×1022m−3. Find the density of conduction electrons in doped semiconductor

Zero

1×109m−3

7×1015m−3

5×1022m−3

ne​.nh​=ni2​ and ne​=nh​=ni​ initially or ni​=7.07×1015m−3 ne​=5×1022(7.07×1015)2​ on ne​≈1×109m−3

Q. In an intrinsic semiconductor, the density of conduction electrons is $7.07 \times 1 0^{15} m^{- 3} .$ When it is doped with indium, the density of holes becomes $5 \times 1 0^{22} m^{- 3}$ . Find the density of conduction electrons in doped semiconductor

$1 \times 1 0^{9} m^{- 3}$

$7 \times 1 0^{15} m^{- 3}$

$5 \times 1 0^{22} m^{- 3}$

$n_{e} . n_{h} = n_{i}^{2}$
and $n_{e} = n_{h} = n_{i}$ initially
or $n_{i} = 7.07 \times 1 0^{15} m^{- 3}$
$n_{e} = \frac{( 7.07 \times 1 0 ^{15} ) ^{2}}{5 \times 1 0 ^{22}}$
on $n_{e} \approx 1 \times 1 0^{9} m^{- 3}$