In an inductor, the current I varies with time t as I=5 A+16( A / s ) t. If induced emf in the inductor is 5 mV, the self inductance of the inductor is

Question

In an inductor, the current I varies with time t as I=5 A+16( A / s ) t. If induced emf in the inductor is 5 mV, the self inductance of the inductor is (A) 3.75 × 10-3 H (B) 3.75 × 10-4 H (C) 3.125 × 10-3 H (D) 3.125 × 10-4 H

Tardigrade Admin · Accepted Answer

I=5+16 t ⇒ (d i/d t)=16 ε=5 × 10-3 V |ε|=(L d i/d t)=L(16)=5 × 10-3 So, L=3.125 × 10-4 H

Q. In an inductor, the current $I$ varies with time $t$ as $I = 5 A + 16 (A / s) t$ . If induced emf in the inductor is $5 mV$ , the self inductance of the inductor is

$3.75 \times 1 0^{- 3} H$

$3.75 \times 1 0^{- 4} H$

$3.125 \times 1 0^{- 3} H$

$3.125 \times 1 0^{- 4} H$

$I = 5 + 16 t$
$\Rightarrow \frac{d i}{d t} = 16$
$ε = 5 \times 1 0^{- 3} V$
$∣ ε ∣ = \frac{L d i}{d t} = L (16) = 5 \times 1 0^{- 3}$
So, $L = 3.125 \times 1 0^{- 4} H$

Q. In an inductor, the current I varies with time t as I=5A+16(A/s)t. If induced emf in the inductor is 5mV, the self inductance of the inductor is

3.75×10−3H

3.75×10−4H

3.125×10−3H

3.125×10−4H