In an experiment with potentiometer, a cell of emf 1.25 V gives a balance point at 35 cm length of the wire. If the cell is replaced by another cell, the balance point shift to 63 cm. The emf of the second cell is

Question

In an experiment with potentiometer, a cell of emf 1.25 V gives a balance point at 35 cm length of the wire. If the cell is replaced by another cell, the balance point shift to 63 cm. The emf of the second cell is (A) 3.25 V (B) 2.5 V (C) 2.25 V (D) 2 V

Tardigrade Admin · Accepted Answer

Given l1=35 cm, l2=63 cm E1 =1.25 V ; E2=? ∴ (E1/E2) =(l1/l2) E2 =(l2/l1) × E1 =(63/35) × 1.25 =2.25 V

Q. In an experiment with potentiometer, a cell of emf $1.25 V$ gives a balance point at $35 c m$ length of the wire. If the cell is replaced by another cell, the balance point shift to $63 c m$ . The emf of the second cell is

3.25 V

2.5 V

2.25 V

2 V

Given $l_{1} = 35 c m, l_{2} = 63 c m$
$E_{1} = 1.25 V; E_{2} = ?$
$∴ \frac{E _{1}}{E _{2}} = \frac{l _{1}}{l _{2}}$
$E_{2} = \frac{l _{2}}{l _{1}} \times E_{1}$
$= \frac{63}{35} \times 1.25$
$= 2.25 V$

Q. In an experiment with potentiometer, a cell of emf 1.25V gives a balance point at 35cm length of the wire. If the cell is replaced by another cell, the balance point shift to 63cm. The emf of the second cell is

3.25 V

2.5 V

2.25 V

2 V

Given l1​=35cm,l2​=63cm E1​=1.25V;E2​=? ∴E2​E1​​=l2​l1​​ E2​=l1​l2​​×E1​ =3563​×1.25 =2.25V

Q. In an experiment with potentiometer, a cell of emf $1.25 V$ gives a balance point at $35 c m$ length of the wire. If the cell is replaced by another cell, the balance point shift to $63 c m$ . The emf of the second cell is

Given $l_{1} = 35 c m, l_{2} = 63 c m$
$E_{1} = 1.25 V; E_{2} = ?$
$∴ \frac{E _{1}}{E _{2}} = \frac{l _{1}}{l _{2}}$
$E_{2} = \frac{l _{2}}{l _{1}} \times E_{1}$
$= \frac{63}{35} \times 1.25$
$= 2.25 V$