In an experiment of CE configuration of n - p - n transistor, the transfer characteristics are observed as given in figure. If the input resistance is 200 Ω and output resistance is 60 Ω the voltage gain in this experiment will be

Question

In an experiment of CE configuration of n - p - n transistor, the transfer characteristics are observed as given in figure. <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/a06f71639a5df94544e2f23a72b84000-.png" /> If the input resistance is 200 Ω and output resistance is 60 Ω the voltage gain in this experiment will be  (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Voltage Gain =( I C / I B ) × ( R 0/ R I )=(10 × 10-3/200 × 10-6) × (60/200)=15

Q. In an experiment of CE configuration of $n - p - n$ transistor, the transfer characteristics are observed as given in figure.

If the input resistance is $200 Ω$ and output resistance is $60 Ω$ the voltage gain in this experiment will be ___

Voltage Gain $= \frac{I _{C}}{I _{B}} \times \frac{R _{0}}{R _{I}} = \frac{10 \times 1 0 ^{- 3}}{200 \times 1 0 ^{- 6}} \times \frac{60}{200} = 15$

Q. In an experiment of CE configuration of n−p−n transistor, the transfer characteristics are observed as given in figure. If the input resistance is 200Ω and output resistance is 60Ω the voltage gain in this experiment will be ___

Voltage Gain =IB​IC​​×RI​R0​​=200×10−610×10−3​×20060​=15

Q. In an experiment of CE configuration of $n - p - n$ transistor, the transfer characteristics are observed as given in figure.

If the input resistance is $200 Ω$ and output resistance is $60 Ω$ the voltage gain in this experiment will be ___

Voltage Gain $= \frac{I _{C}}{I _{B}} \times \frac{R _{0}}{R _{I}} = \frac{10 \times 1 0 ^{- 3}}{200 \times 1 0 ^{- 6}} \times \frac{60}{200} = 15$