In an experiment, 0.04 F was passed through 400 mL of a 1 M solution of NaCl. What would be the pH of the solution after the electrolysis?

Question

In an experiment, 0.04 F was passed through 400 mL of a 1 M solution of NaCl. What would be the pH of the solution after the electrolysis? (A) 8 (B) 10 (C) 13 (D) 6

Tardigrade Admin · Accepted Answer

Electrolysis of NaCl (aq) gives hydrogen gas at cathode and oxygen gas at anode, the electrolyte solution contains NaOH after electrolysis.

Number of equivalents (W/E) of NaOH formed = 0.04

Normality

= \frac{W}{E \times V} \times 1000

Normality,

N = \frac{0.04 \times 1000}{400} = 0.1

[O H^{-}] = 0.1

M

pOH

= 1

So pH = 13.

Q. In an experiment, 0.04 F was passed through 400 mL of a 1 M solution of NaCl. What would be the pH of the solution after the electrolysis?

8

10

13

6

Electrolysis of NaCl (aq) gives hydrogen gas at cathode and oxygen gas at anode, the electrolyte solution contains NaOH after electrolysis. Number of equivalents (W/E) of NaOH formed = 0.04 Normality =E×VW​×1000 Normality, N=4000.04×1000​=0.1 [OH−]=0.1 M pOH =1 So pH = 13.